49x^2+35x-6=0

Solution for 49x^2+35x-6=0 equation:

49x^2+35x-6=0

a = 49; b = 35; c = -6;
Δ = b2-4ac
Δ = 352-4·49·(-6)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-49}{2*49}=\frac{-84}{98}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+49}{2*49}=\frac{14}{98}
=1/7
$